Documented in this article is a common question relating to the inverter current draw and a breakdown of expectant voltage and efficiencies.
Question - How much current is drawn from the 12V (or 24V) battery when running an inverter connected to a battery? Answer - The simple answer is- divide the load watts by 10 (20). E.g. For a load of 300 Watts, the current drawn from the battery would be: 300 ÷ 10 = 30 Amps (300 ÷ 20 = 15 Amps) Notes - It is the actual load watts, not the inverter rating that counts. Therefore, a 1500W inverter with a 500 Watt load would be 50 (25) Amps, not 150 (75) Amps. The same inverter with a 1200 Watt load would draw 120 (60) Amps. How long will my battery last with an inverter load of 1000 Watts? For a more accurate calculation of battery current: Divide load watts by actual battery voltage, this will be in the range 12-14V (24-28V). Then to allow for inverter efficiency, typically 85%, divide the figure by 0.85. Thus: For a 300W load at 12V....300 ÷ 12 ÷ 0.85 = 29.4 Amps. For a 300W load at 14V....300 ÷ 14 ÷ 0.85 = 25.2 Amps. You can see the simple divide by 10 gives an easy "worst case" guide. Similarly: For a 300W load at 24V....300 ÷ 24 ÷ 0.85 = 14.7 Amps. For a 300W load at 28V....300 ÷ 28 ÷ 0.85 = 12.6 Amps. You can see the simple divide by 20 gives an easy "worst case" guide. Note: Figures in brackets are for 24V systems.
1 Comment
31/10/2019 09:25:03 pm
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AuthorFrik Stuart - Entrepreneur & DCV technology enthusiast. Archives
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